If the letters of the word "$ASSASSINATION$" are arranged at random in a row,then the probability that no two $A$'s come together is equal to

  • A
    $\frac{25}{26}$
  • B
    $\frac{23}{26}$
  • C
    $\frac{15}{26}$
  • D
    $\frac{17}{26}$

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If three distinct numbers are chosen randomly from the first $100$ natural numbers,then the probability that all three of them are divisible by both $2$ and $3$ is

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